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A girl sits on a tire swing and is pushed in a circular motion by her father. Her tangential speed is 2.8 m/s and the girl travels in a circle with a diameter of 4.0 m. What is the girls centripetal acceleration?

Respuesta :

claytonbeast22
Formula: Ca=Vt^2/r

centripetal acceleration(Ca)= ?
tangential speed(Vt)= 2.8m/s
Radius(r)=2m

Substitute: Ca=2.8^2/2
                  Ca=3.92m/s^2

Answer:

The girl's centripetal acceleration is 3.92 m/s².

Explanation:

Given that,

Tangential speed = 2.8 m/s

Diameter = 4.0 m

We need to calculate the centripetal acceleration

Using formula of centripetal acceleration

[tex]\alpha=\dfrac{v^2}{r}[/tex]

Where, v = tangential speed

r = radius

Put the value into the formula

[tex]\alpha=\dfrac{2.8^2}{2.0}[/tex]

[tex]\alpha=3.92\ m/s^2[/tex]

Hence, The girl's centripetal acceleration is 3.92 m/s².

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