Respuesta :

Hagrid

Given:

                5 kg of coal

                T1 = 20°C, T2 = 220°C

 

Required:

                Q(heat energy)

 

                Solution:

                The specific heat of coal (bituminous) is 1.315 kJ/kg-K

 

                Q = mcp(T2-T1)

                Q = 5kg (1.315 kJ/kg-K) (220 – 20)

                Note that T(°C) = T(K)

                Q = 1315 kJ or 1315000 J

                Since  1315000 J is close to 1314718 J, the answer is letter A.

johanrusli

1.3 × 10⁶ Joules of heat is required to raise the temperature of 5 kilograms of coal from 20°C to 220°C

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Further explanation

Specific Heat Capacity is the amount of energy needed to raise temperature of 1 kg body for 1°C.

[tex]\large {\boxed{Q = m \times c \times \Delta t} }[/tex]

Q = Energy ( Joule )

m = Mass ( kg )

c = Specific Heat Capacity ( J / kg°C )

Δt = Change In Temperature ( °C )

Let us now tackle the problem!

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Given:

mass of coal = m = 5 kg

change in temperature = Δt = 220 - 20 = 200°C

specific heat capacity of coal = c = 1.3 × 10³ J/kg°C

Asked:

heat required = Q = ?

Solution:

[tex]Q = mc\Delta t[/tex]

[tex]Q = 5 \times (1.3 \times 10^3) \times 200[/tex]

[tex]Q = 1.3 \times 10^6 \texttt{ Joules}[/tex]

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Conclusion:

1.3 × 10⁶ Joules of heat is required to raise the temperature of 5 kilograms of coal from 20°C to 220°C

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Learn more

  • Efficiency of Engine : https://brainly.com/question/5597682
  • Flow of Heat : https://brainly.com/question/3010079
  • Difference Between Temperature and Heat : https://brainly.com/question/3821712

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Answer details

Grade: College

Subject: Physics

Chapter: Thermal Physics

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