Respuesta :

Exvited
[tex]28y^2+43y-48 \\ \\ 28y^2 + 64y - 21y - 48 \ / \ factor \\ \\ 4y(7y + 16) - 3(7y + `16) \ / \ factor \ out \ common \ terms \\ \\ (7y + 16)(4y - 3) \ / \ factor \ out \ 7y + 16 \\ \\ [/tex]

So, your answer to this problem is (7y + 16)(4y - 3).
Billymkhoi
28y^2+ 43y -48
= 28x^2 +(-21x+ 64x) -48
= (28x^2 -21x)+ (64x -48)
= 7x* (4x -3)+ 16* (4x -3)
= (4x -3)(7x+ 16)

Final answer: (4x -3)(7x+ 16).