Respuesta :

AL2006

If they were all the same integer, then each one would be
1/3 of 36, and you would have

                                           12  +  12  +  12  =  36 .

But you don't want them to all be the same number.  You
want them to be three consecutive even numbers.

Fine !  Take 2 away from the first 12, and glue it onto the last 12 .
Their sum doesn't change, but now you have

                                             10  +  12  +  14  =  36 .
First, I would set up an equation (assuming 36 is the sum of all 3 numbers). 

x+(x+2)+(x+4)=36
               3x+6=36
                   -6   -6
                   3x=30
                   ---   ---
                   3     3
                   x=10

Now, we just plug in the numbers to find the consecutive integers
10+(10+2)+(10+4)
10+12+14

So your 3 consecutive even integers are 10,12 and 14


Otras preguntas