Respuesta :
[tex]5x^2+2x-1=0[/tex]
Delta equation is:
[tex]\Delta =\frac{-b\pm\sqrt(b^2-4ac)}{2a}[/tex]
but we are interested in [tex]b^2-4ac[/tex] because it determines the discriminant
[tex]5^2-4*2*(-1)=25+8=33[/tex]
[tex]33>0[/tex]
which means that discriminant is positive :)
Delta equation is:
[tex]\Delta =\frac{-b\pm\sqrt(b^2-4ac)}{2a}[/tex]
but we are interested in [tex]b^2-4ac[/tex] because it determines the discriminant
[tex]5^2-4*2*(-1)=25+8=33[/tex]
[tex]33>0[/tex]
which means that discriminant is positive :)
Answer:
The discriminant of the quadratic equation is 24 .
Step-by-step explanation:
Discriminant form of the quadratic equation .
D = b² - 4ac
As the quadratic equation in the form.
2x + 5x² = 1
Simplify the above term
5x² + 2x - 1 = 0
As the quadratic equation in the form
ax² + bx + c =0
Here a = 5 , b = 2 , c= -1
put in the formula
D = 2 × 2 - 4× 5 × -1
D = 4 +20
D = 24
Therefore the discriminant of the quadratic equation 5x² + 2x - 1 = 0 is 24 .