Answer: see the last column in the final table of the explanation below.
Explanation:
1) Arrange the data to understand the question:
Acid Molarity Moles of H⁺ released per liter
HCl 1 ____
H2SO4 1 ____
H3PO4 1 ____
H2SO4 0.5 ____
H3PO4 3 ____
HNO3 2 ____
2) All the given acids are strong acids, so you can consider they dissociate completely and release all the hydrogens present in the chemical formula.
3) The molarity formula is M = n/V, where n is the number of moles of solute and V is the volume of the solution in liters
From that, n = M×V
Go one by one with that formula.
Acid Molarity Moles of solute number of H in Moles H⁺ per liter the chemical formula per liter
HCl 1 1M×1L = 1 1 1×1 = 1
H₂SO4₄ 1 1M×1L = 1 2 2×1 = 2
H₃PO₄ 1 1M×1L = 1 3 3×1 = 3
H₂SO₄ 0.5 0.5M×1L = 0.5 2 2×0.5 = 1
H₃PO₄ 3 3M×1L = 3 3 3×3 = 9
HNO₃ 2 2M×1L = 2 2 2×2 = 4
