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He probability of choosing a vowel (a, e, i, o, or u) from a deck of cards containing the 26 letters of the alphabet is shown below. what is the probability of choosing the letters a and e one after the other without replacement?

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jcherry99
Small. very small.

Out of 26 cards, you must choose one of them -- an "a". That's 1/26.

There are 25 cards left and again you must choose one of them. That's one out of 25. or 1/25.

The probability can only be 1/26 * 1/25 = 1/650

Put another way, if you played this game 650 times, you would only choose an a first and an e second once.   
konrad509
[tex]|\Omega|=26\cdot25=650\\ |A|=1\\\\ P(A)=\dfrac{1}{650}\approx0.15\%[/tex]

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