Answer:
[tex]0.362-0.045<p<0.362+0.045[/tex]
Step-by-step explanation:
It is given that When 415 junior college students were surveyed, 150 said they have a passport, then sample proportion will be:
Sample proportion=[tex]\frac{150}{415}=0.362[/tex]
Then, [tex]ME=1.96\sqrt{\frac{0.362{\times}0.638}{415}}[/tex]
=[tex]1.96\sqrt{\frac{0.230}{415}[/tex]
=[tex]1.96(0.023)[/tex]
=[tex]0.045[/tex]
Therefore, at 95% confidence interval, the proportion of junior college students that have a passport is:
[tex]0.362-0.045<p<0.362+0.045[/tex]
