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At a local baseball game there are 3 hot dog vendors. collectively the vendors sold 1,700 hot dogs. if vendor a sold 456, vendor b sold 607, and vendor c sold 637, what percentage of the total did each vendor sell? (round to the nearest percent.) a) 26 percent, 40 percent, 44 percent b) 45 percent, 37 percent, 18 percent c) 27 percent, 36 percent, 37 percent d) 30 percent, 35 percent, 35 percent

Respuesta :

Skøll1922
456×100÷1700≈26.8
607×100÷1700≈35.7
637×100÷1700≈37.4

So the answer is C)27%, 36%, 37%.

Hope this helped!

Answer:

c) 27 percent, 36 percent, 37 percent

Step-by-step explanation:

Given,

Hot dogs sold by,

Vendor a = 456

Vendor b = 607

Vendor c = 637,

Total hot dogs = 1700,

Thus, the percentage of the hot dogs sold by a = [tex]\frac{\text{Hot dog sold by a}}{\text{Total hot dogs}}\times 100[/tex]

[tex]=\frac{456}{1700}\times 100[/tex]

[tex]=\frac{456}{17}[/tex]

= 26.82%

≈ 27%

Similarly,

Percentage of the hot dogs sold by a

[tex]=\frac{607}{1700}\times 100[/tex]

[tex]=\frac{607}{17}[/tex]

= 35.71%

≈ 36%

Percentage of the hot dogs sold by a

[tex]=\frac{637}{1700}\times 100[/tex]

[tex]=\frac{637}{17}[/tex]

= 37.47%

≈ 37%

Hence, OPTION c) is correct.

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