The net ionic equation for the reaction between aqueous sulfuric acid and aqueous sodium hydroxide is ________.
a.h+ (aq) + hso4- (aq) + 2oh- (aq) → 2h2o (l) + so42- (aq)
b.h+ (aq) + hso4- (aq) + 2na+ (aq) + 2oh- (aq) → 2h2o (l) + 2na+ (aq) + so42-(aq)
c.so42- (aq) + 2na+ (aq) → 2na+ (aq) + so42-(aq)
d.h+ (aq) + oh- (aq) → h2o( l)
e.2h+ (aq) + so42- (aq) + 2na+ (aq) + 2oh- (aq) → 2h2o (l) + 2na+ (aq) + so42- (aq)

Respuesta :

Molecular equation:
[tex]H_{2}SO_{4}(aq) + 2NaOH(aq)--\ \textgreater \ Na_{2}SO_{4}(aq) + 2H_{2}O(l) Complete ionic equation: 2H^{+}+SO_{4}^{2-} + 2Na^{+} +2OH^{-}--\ \textgreater \ 2Na^{+}+SO_{4}^{2-} + 2H_{2}O(l) Near 2H^{+},SO_{4}^{2-} , 2Na^{+} , OH^{-} should be written (aq). Remove ions that do not change from both sides 2H^{+} + 2OH^{-}=2H_{2}O Net ionic equation: H^{+}(aq) + OH^{-}(aq)=H_{2}O(l) Answer is D. [/tex]