Respuesta :
EQUATION OF A LINE IS Y-Y¹ =m(X-X¹)
WHERE M IS SLOPE
SO
EQUATION OF LINE IS Y-0={(8-0)/(3-6)}[X-6]
¶¶ Y= (-8/3)(X-6)
HERE YOU GO---- {3Y+8X-48=0}
HOPE THIS IS HELPFUL
WHERE M IS SLOPE
SO
EQUATION OF LINE IS Y-0={(8-0)/(3-6)}[X-6]
¶¶ Y= (-8/3)(X-6)
HERE YOU GO---- {3Y+8X-48=0}
HOPE THIS IS HELPFUL
To begin this problem, we need to use the two points that we are given to find the slope of the line. Slope is defined as the change in y values divided by the change in x values, or rise/run, and is represented by the variable m.
m = (y1-y2)/(x1-x2) = (8-0)/(3-6) = 8/(-3) = -8/3
Now, we can use the slope and one of the points from our given values to create an equation of the line in point-slope form.
y = m(x-h) + k, where a point on the line is (h,k)
y = -8/3(x - 3) + 8
Now, we can distribute our slope and simplify through addition.
y = -8/3x + 8 + 8
y = -8/3x + 16
Therefore, your answer is y = -8/3x + 16.
Hope this helps!