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Use the graph below to answer the question that follows:
cosine graph with points at 0, negative 1 and pi over 3, 0 and pi, 3 and 5 pi over 3, 0 and 2 pi, negative 1

What are the amplitude, period, and midline of the function?

Amplitude: 4; period: π; midline: y = 2
Amplitude: 2; period: 2π; midline: y = 1
Amplitude: 4; period: 2π; midline: y = 1
Amplitude: 2; period: π; midline: y = 2

Use the graph below to answer the question that follows cosine graph with points at 0 negative 1 and pi over 3 0 and pi 3 and 5 pi over 3 0 and 2 pi negative 1 class=

Respuesta :

carlosego
For this case the amplitude is given by:
 A = (l-1l + 3) / 2
 A = 4/2
 A = 2
 The middle line is given by:
 y = 1
 The period of the function is given by:
 T = l x2 - x1 l
 T = l 0 - 2pi l
 T = l - 2pi l
 T = 2pi
 Answer:
 Amplitude: 2; period: 2π; midline: y = 1

Answer:

For this case the amplitude is given by:

A = (l-1l + 3) / 2

A = 4/2

A = 2

The middle line is given by:

y = 1

The period of the function is given by:

T = l x2 - x1 l

T = l 0 - 2pi l

T = l - 2pi l

T = 2pi

Answer:

Amplitude: 2; period: 2π; midline: y = 1

Step-by-step explanation:

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