Consider 2NH3(g)+3CuO(s)→N2(g)+3Cu(s)+3H2O(g) 2NH 3 ​ (g)+3CuO(s)→N 2 ​ (g)+3Cu(s)+3H 2 ​ O(g). What volume (in mL) of NH3 NH 3 ​ is required to completely react 45.2 g of CuO at STP? Enter your solution as a numerical value with no units.

Respuesta :

the volume of  in Ml  of NH3  required  to completely  react  with  45.2 g  of CUO   at  STP  is 8489.6 Ml

 calculation
calculate the moles  of CUO  used
moles= mass/molar mass
45.2 g/79.5 g/mol =0.569 moles

Reacting  equation 
2NH3  + 3CUO = N2  +3CU  +3H2O
by  use of reacting  ratio  between  NH3 to CUO  which jis  2:3 the moles of  NH3  = 0.569 x2/3 = 0.379 moles

At STP  1  mole  = 22.4 L
what about  0.379 moles

=0.379  x22.4  = 8.4896  L

in  Ml  = 8.4896  x1000 =8489.6 ml