The probability that the result is a multiple of 5 and a multiple of 2 is 6/11
Suppose that there are finite elementary events in the sample space of the considered experiment, and all are equally likely.
Then, suppose we want to find the probability of an event E.
Then, its probability is given as
[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{n(E)}{n(S)}[/tex]
where favorable cases are those elementary events who belong to E, and total cases are the size of the sample space.
For this case, we're given that:
Take E = Event of spinner's spin resulting in multiple of 5 or multiple of 2
S = results of Sample
Then, favorable results (in favor of E) are: 2,4,5,6,8,10 (total 6 in count)
All possible results are 1, 2, ... , 11 (total 11 in count)
Thus, we get:
[tex]P(E) = \dfrac{\text{Number of favorable cases}}{\text{Number of total cases}} = \dfrac{6}{11}[/tex]
Thus, the probability that the result is a multiple of 5 and a multiple of 2 is 6/11
Learn more about probability here:
brainly.com/question/1210781
