A circuit consisting of a 140 µF capacitor in series with a 2 MΩ resistor is connected across a 6 V battery. What is the time constant of the circuit? Answer in units of s.

Respuesta :

The time constant of an RC circuit is given by the product between the resistance and the capacitance of the circuit:
[tex]\tau = RC[/tex]
where R is the resistance and C the capacitance.

For the circuit in our problem, 
[tex]R=2M\Omega = 2 \cdot 10^6 \Omega[/tex]
and
[tex]C=140 \mu F = 140 \cdot 10^{-6}F[/tex]

Therefore, the time constant of this circuit is
[tex]\tau =RC=(2 \cdot 10^{6} \Omega)(140 \cdot 10^{-6} F)=280 s[/tex]