The scores on a university examination are normally distributed with a mean of 62 and a standard deviation of 11. if the bottom 5% of students will fail the course, what is the lowest mark that a student can have and still be awarded a passing grade? give the answer that is closest to the exact number.

The lowest score will be obtained as follows:
the z-score is given by:
z=(x-μ)/σ
where:
σ-standard deviation
μ- mean

we are required to evaluate for x, given that P(x<X)=0.05
The value of z that corresponds to 5% will be:
z=-1.65
thus plugging our values we obtain:
-1.65=(x-62)/11
solving for x we get:
-18.15=x-62
thus
x=-18.15+62
x=43.85
x~44
Thus the lowest score is 44

Answer Link

ahirohit963 ahirohit963 · Answer 2 · 2021-10-18T14:43:25+02:00

The lowest marks that a student can have and still be awarded a passing grade is 44.

Step-by-step explanation:

Given :

Mean, [tex]\mu = 62[/tex]

Standard Deviation, [tex]\sigma = 11[/tex]

Calculation :

z score is given by,

[tex]z = \dfrac{x-\mu }{\sigma}[/tex] ----- (1)

Value of z corresponds to 5% is,

[tex]z =-1.65[/tex]

from equation (1) we get,

[tex]-1.65=\dfrac{x-62}{11}[/tex]

[tex]x=43.85[/tex]

[tex]\rm x = 44 \;\;(Approx)[/tex]

The lowest marks that a student can have and still be awarded a passing grade is 44.

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