Respuesta :
The father is 40 which is 2 less than 7x6=42 Therefore the son is 6. In 3 years the the father will be 43 and the son will be 9. 43+9=52
Answer:
Son’s present age, s = 6 years.
Step-by-step explanation:
Let the son’s present age is s years and father's be f.
We have age of a father is 2 less than 7 times the age of his son.
f = 7s -2
7s - f = 2 -------------------eqn 1
In 3 years, the sum of their ages will be 52.
s + 3 + f + 3 = 52
s + f = 46 -------------------eqn 2
eqn 1 + eqn 2
8s = 48
s = 6
Son’s present age, s = 6 years.