Respuesta :

The father is 40 which is 2 less than 7x6=42  Therefore the son is 6. In 3 years the the father will be 43 and the son will be 9.  43+9=52

Answer:

Son’s present age, s = 6 years.

Step-by-step explanation:

Let the son’s present age is s years and father's be f.

We have age of a father is 2 less than 7 times the age of his son.

            f  = 7s -2

         7s - f = 2 -------------------eqn 1

In 3 years, the sum of their ages will be 52.

         s + 3 + f + 3 = 52

        s + f = 46 -------------------eqn 2

eqn 1 + eqn 2

          8s = 48

            s = 6

Son’s present age, s = 6 years.