The equation for this reaction is as follow,
2 NaN₂ (s) → 2 Na (s) + 3 N₂ (g)
According to equation,
67.2 L N₂ (3 moles) is produced by = 102 g (2 moles) NaN₂
So,
65.1 L N₂ will be produced by = X g of NaN₂
Solving for X,
X = (102 g × 65.1 L) ÷ 67.2
X = 98.81 g of NaN₂
Result:
98.81 g of NaN₂ is required to produce 65.1 L N₂ to inflate airbag.
