Respuesta :
[tex]\bf s(t)=-9-5y\implies \left. \stackrel{v(t)}{\cfrac{ds}{dt}=-5} \right|_{t=4}\implies -5[/tex]
since the derivative is a constant, it doesn't quite matter what "t" may be.
since the derivative is a constant, it doesn't quite matter what "t" may be.
Answer:
Instantaneous Velocity is [tex]-5[/tex]
Step-by-step explanation:
Velocity refers to the speed along with direction or we can say velocity refers to rate of change of position of an object with respect to time.
Let [tex]s\left ( t \right )[/tex] be the position of object . Then the instantaneous velocity is given by [tex]v\left ( t \right )=s'\left ( t \right )[/tex] . At time [tex]t=t_0[/tex] , velocity is given by [tex]v\left ( t_0 \right )=s'\left ( t_0 \right )[/tex]
Given: [tex]s\left ( t \right )=-9-5t[/tex]
On differentiating with respect to time t , we get :
[tex]v\left ( t \right )=s'\left ( t \right )=-5[/tex]
At [tex]t=t_0=4[/tex] ,
[tex]v\left ( 4 \right )=s'\left ( 4 \right )=-5[/tex]
