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Write the equation of the circle with center (−3, −2) and (4, 5) a point on the circle.

Respuesta :

popalabdulqayou
1. distance = √((x₂-x₁)²+(y₂-y₁)²)= radius of the circle.

distance = √((4-(-3))²+(5-(-2))7²) = √98

2. (x-k)²+(y-h)²=r² center (-3,-2) which is (k,h)

(x-(-3))²+(y-(-2))²= (√98)²

(x+3)+(y+2)² = 98 is the equation
TheBrokenMarionette

Answer:

B.  (x + 3)^2 + (y + 2)^2 = 98

Step-by-step explanation:

(x + 3)^2 + (y + 2)^2 = 98

r =(sqroot)   (x − h^)2 + (y − k)^2

r =(sqroot)   (4 − (−3)^2 + (5 − (−2)^2

r =  (sqroot) 7^2 + 7^2

r =  (sqroot) 49 + 49

r =(sqroot)   98

x^2 + y^2 = r^2

(x − (−3)^2 + (y − (−2)^2 = (sqroot) ( 98)^2

(x + 3)^2 + (y + 2)^2 = 98

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