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Shape I is similar to shape II.
The sequence of transformations applied to shape I that proves shape I is similar to shape II is a reflection across the ____ , and then a dilation by a scale factor of ____ .

Shape I is similar to shape II The sequence of transformations applied to shape I that proves shape I is similar to shape II is a reflection across the and then class=
Shape I is similar to shape II The sequence of transformations applied to shape I that proves shape I is similar to shape II is a reflection across the and then class=
Shape I is similar to shape II The sequence of transformations applied to shape I that proves shape I is similar to shape II is a reflection across the and then class=

Respuesta :

kanest
Shape I is located in quadrant IV. Shape II is located in quadrant III.

Shape I has positive x-values and negative y-values.
Shape II has negative x-values and negative y-values.

From this information, we can conclude that shape I was reflected over the y-axis.

This shape has a defined length that we can use to find the scale dilation.

Look at the points (2,-4) and (5,-4) on shape I. These points represent corners of the shape, and we can use these points to find the length of the shape by subtracting the x-values as an absolute value:

[tex]|5 - 2| = 3[/tex]

The length of the shape is 3 units.

Now we'll look at shape II.

The same line that we used in shape I is present on points (-7.5,-6) and (-3,-6). We can find the length by subtracting the x-values as an absolute value:

[tex]|-7.5 - (-3)| = |-4.5| = 4.5[/tex]

The length of shape II is 4.5.

Divide the length of shape II by the length of shape I:

[tex]4.5 \div 3 = 1.5[/tex]

The dilation's scale factor is 1.5.
MrRoyal

The complete statement is:

The sequence of transformations applied to shape I that proves shape I is similar to shape II is a reflection across the y-axis, and then a dilation by a scale factor of 1.5.

From the figure, we can see that both shapes are on either sides of the vertical axis.

This means that:

Shape I is reflected across the y-axis.

Also, the measures of one of the corresponding sides of both shapes are:

Shape I = 2

Shape II = 3

So, the scale factor is:

[tex]\mathbf{k = \frac{Shape\ II}{Shape\ I}}[/tex]

This gives

[tex]\mathbf{k = \frac{3}{2}}[/tex]

[tex]\mathbf{k = 1.5}[/tex]

Hence, the scale factor is 1.5

Read more about transformations at:

https://brainly.com/question/12009346

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