Respuesta :
Answer:
x^2 -1.6x + y^2 +1.2y+0.8 =0
Step-by-step explanation:
Rewrite the equation of the circle (x − 0.8)^2 + (y + 0.6)^2 = 0.2 in general form
General form is
x^2 + y^2 + gx^2 + fy^2 +c =0
So we expand (a-b)^2
(a-b)^2= a^2 -2ab + b^2
x^2-1.6x+0.64 + y^2+1.2y+0.36 =0.2
Make right hand side 0, subtract 0.2 from both sides
x^2-1.6x+0.64 + y^2+1.2y+0.36 -0.2=0
x^2 -1.6x + y^2 +1.2y+ 1-0.2 =0
x^2 -1.6x + y^2 +1.2y+0.8 =0
