The initial height of the first body is given by:
[tex]h_1 = \frac{1}{2}gt^2 [/tex]
where
g is the gravitational acceleration
t is the time it takes for the body to reach the ground
Substituting t=1 s, we find
[tex]h_1 = \frac{1}{2}(9.81 m/s^2)(1 s)^2=4.9 m [/tex]
The second body takes takes t=2 s to reach the ground, so it was located at an initial height of
[tex]h_2 = \frac{1}{2}(9.81 m/s^2)(2 s)^2=19.6 m [/tex]
The second body started its fall 1 second before the first body, therefore when the second body started its fall, the first body was located at its initial height, i.e. at 4.9 m from the ground.
