For this case, we can model the problem as a triangle with a right angle.
Where,
x, y: lengths of the sides of the triangle
d: hypotenuse of the triangle
We then have the following relationship:
[tex]d ^ 2 = x ^ 2 + y ^ 2
[/tex]
Clearing d we have:
[tex]d = \sqrt{ x^2 + y^2} [/tex]
Answer:
A functions that would best model the situation above is:
D square root