The electrostatic force between two charged object is given by:
[tex]F=k \frac{q_1 q_2}{r^2} [/tex]
where
k is the Coulomb's constant
q1 and q2 are the charges of the two objects
r is the separation between the two objects
We see that the force is inversely proportional to the square of the distance: [tex] \frac{1}{r^2} [/tex]. Therefore, if the distance is doubled, the force decreases by a factor 4, and the new force will be:
[tex]F'= \frac{F}{4}= \frac{0.32 N}{4}=0.08 N [/tex]
and it will still be a repulsive force, since the two balloons have charges of same sign.
