Total number of chips = 4+ 6 = 10
Number of white chips = 4
Probability of picking a white chip = [tex] \frac{4}{10}= \frac{2}{5} [/tex]
This white chip is not replaced back into the bag. This will reduce the number of white chips in the bag by 1 and reduce the total number of chips in the bag by 1.
So, now the total number of chips in the bag = 3 + 6 = 9
Number of white chips in the bag = 3
Probability of picking a white chip = [tex] \frac{3}{9}= \frac{1}{3} [/tex]
Thus, the probability of picking two white chips will be = [tex] \frac{2}{5}* \frac{1}{3}= \frac{2}{15} [/tex]
Therefore, option B gives the correct answer.
