kingshoozil
kingshoozil
06-07-2018
Mathematics
contestada
−4z+31≥17z+23 solve for z show steps
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altavistard
altavistard
06-07-2018
Combine like terms: −4z+31≥17z+23 becomes 31 ≥ 21z + 23, and 31 ≥ 21z + 23 becomes 8 ≥ 21z.
To solve for z, divide both sides of this inequality by 21: 8/21 ≥ z, or z ≤ 8/21.
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st4rgrl
st4rgrl
06-07-2018
The answer is [tex] \frac{8}{21} [/tex]≥z.
-4z+31
≥17z+23
+4z +4z
----------------------
31
≥21z+23
-23 -23
-----------------------
8
≥21z
--- -----
21 21
[tex] \frac{8}{21} [/tex]≥z
Answer Link
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