The trick with these is to just try a number. c=1
( (6+3)/(-4+2) ) / ( (2+1)/(4-2) ) = (9/-2)/(3/2)) = -3
Last choice.
If there was a none of the above we'd have to do the algebra, which is straightforward:
[tex]\dfrac{ \frac{6c^2+3c}{-4c+2} } { \frac{2c + 1}{4c - 2} }=\dfrac{6c^2+3c}{-4c+2} \cdot \dfrac{4c - 2}{2c + 1}[/tex]
[tex]=\dfrac{4c-2}{-4c+2}\cdot\dfrac{6c^2+3c}{2c + 1}[/tex]
[tex]=(-1)\cdot\dfrac{3c(2c+1)}{2c + 1}[/tex]
[tex]=-3c[/tex]
