Respuesta :

1.1 / 2 = .7 --> 2.86 yrs

.7 / 2 = .45 —> 5.72 yrs

.45 / 2 = .225 —> 8.58 yrs

.225 / 2 = .1125 —> 11.44 yrs

So, for the sample of plutonium to reach .140 mg it should take a little less than 11.44 years.

Hope this helps

11.44 years it will take for the 1.10 mg sample of pu−236 to decay to 0.140 mg.

What is half life time?

Half life time is the time in which concentration of reactant becomes half of the initial concentration.

Total time for the decomposition of pu-236 to 0.140mg is calculated as:

T = (t)ⁿ, where

t = half life time = 2.86 years (given)

n = no. of half life time required

1.1/2 → 0.7     .......... 2.86 yrs (1st half life)

0.7/2 → 0.45 .......... 5.72 yrs (2nd half life)

0.45/2 → 0.225 ..... 8.58 yrs (3rd half life)

0.225/2 → 0.1125 ... 11.44 yrs(4th half life)

Here, n = 4

T = (2.86)⁴ = 11.44 years

Hence, we require little more time than 11.44 years.

To know more about half life time, visit the below link:

https://brainly.com/question/26689704