danielthomaskoleth danielthomaskoleth

06-08-2018
Mathematics

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if alpha and beta are the zeroes of the polynomial 6y^2(six y squared) - 7y + 2, find a quadratic polynomial whose zeroes are 1/alpha +1/beta

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lesliekolleroxrkcf lesliekolleroxrkcf

07-08-2018

6y² - 7y + 2 = 0
y=7±√(49-4*6*2) / 12

= 7±1 / 12

= ½ or ⅔

so we want our polynomial to have roots of 2 and 3/2

(x-2)(x-3/2)=0
x²- 7/2x +3 = 0

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