we have given that circumference of a right cylinder.
[tex] C=2\pi r=9\pi ,r=9/2cm [/tex]
where the base in circular.
[tex] h=2r,h=2*9/2=9cm [/tex]
we know that surface area [tex] =2\pi rh=2*\pi *9/2*9=81\pi ,cm^2 [/tex]=[tex] 254.5cm^2 [/tex]
surface area=[tex] 2\pi rh+2\pi r^2=81\pi +9\pi *(9/2)=381.7cm^2 [/tex].