Company A charges $0.32 dollars per minute (no fixed monthly charge). Company B charges $13.9 per month plus $0.28 per minute. Company C charges a fixed rate of $50 per month. Let (), (), and () denote the monthly charges of Company A, B, and C respectively for spending minutes on long distance calls.
Find a formula for the monthly cost of using Company A, A(x):A(x)= 
Find a formula for the monthly cost of using Company B, B( X ): B(X) = 
Find a formula for the monthly cost of using Company C, C(X): C(X) =

Respuesta :

For this case, the first thing we must do is define variables.

We have then:

x: number of minutes

A (x), B (x), C (x): total cost of companies A, B and C, respectively.

We must write a function of the form:

[tex] f (x) = mx + b [/tex]

Where,

m: is the cost per minute

b: it is the fixed cost.

For the company A we have:

[tex] A (x) = 0.32x [/tex]

For company B we have:

[tex] B (x) = 0.28x + 13.9 [/tex]

For company C we have:

[tex] C (x) = 50 [/tex]

Answer:

The cost of each company monthly is:

[tex] A (x) = 0.32x [/tex]

[tex] B (x) = 0.28x + 13.9 [/tex]

[tex] C (x) = 50 [/tex]

For this case, the first thing we must do is define variables.

We have then:

x: number of minutes

A (x), B (x), C (x): total cost of companies A, B and C, respectively.

We must write a function of the form:

[tex] f (x) = mx + b [/tex]

Where,

m: is the cost per minute

b: it is the fixed cost.

For the company A we have:

[tex] A (x) = 0.32x [/tex]

For company B we have:

[tex] B (x) = 0.28x + 13.9 [/tex]

For company C we have:

[tex] C (x) = 50 [/tex]

Answer:

The cost of each company monthly is:

[tex] A (x) = 0.32x [/tex]

[tex] B (x) = 0.28x + 13.9 [/tex]

[tex] C (x) = 50 [/tex]