So to find the constant of a perfect square, divide the x coefficient by 2 and then square that quotient.
*Remember that dividing by a number is the same as multiplying by the reciprocal.
[tex]-\frac{3}{4}\times \frac{1}{2}=-\frac{3}{8}\\\\(-\frac{3}{8})^2=-\frac{3}{8}\times-\frac{3}{8}=\frac{9}{64}[/tex]
You need to add 9/64 on both sides of the equation for this to be a perfect square.
