[tex]\dfrac{2}{3}x+\dfrac{1}{2}=10\ \ \ \ |-\dfrac{1}{2}\\\\\dfrac{2}{3}x=9\dfrac{1}{2}\\\\\dfrac{2}{3}x=\dfrac{19}{2}\ \ \ \ |\cdot\dfrac{3}{2}\\\\x=\dfrac{57}{4}[/tex]
