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How much work (in joules) is done in moving a charge of 2.5 μc a distance of 35 cm along an equipotential at 12 v? do not include units with your answer?

Respuesta :

Blacklash

The work done for moving a charge is due to the change in potential between the points. That is the work done is given by the expression W = qΔV. Where q is the charge and ΔV is the change in potential between two points.

In case of equipotential lines the value of potential is same at all the points.

So the value of ΔV when moving along a equipotential line is zero.

So W = qΔV = q*0=0

So no work is needed to move charge along an equipotential line.

Work done = 0

adefioyelaoye

The work done for moving a charge along an equipotential at

12v is 0J.

What is Work done?

This is defined as the force taken to move an object multiplied

by the total distance moved.

Work done = qΔV.

where q is the charge , ΔV is the change in potential between two points.

In scenarios involving equipotential lines, the value of potential

is same at all the points.

This means that the value of ΔV when moving along a

equipotential line is 0.

W = qΔV = q*0=0

This therefore means that no work is done = 0J

Read more about Work done here  https://brainly.com/question/25573309

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