Respuesta :
1 molar (M) solution is equivalent to the 1 mole of the compound present in 1 litter or 1000 mL of the solution. Thus 1.27 M (molar) solution represent 1.27 mole of K₃PO₄ present in 1000 mL of the solution. Thus 343 mL of the solution contains [tex]\frac{1.27}{1000}[/tex]×343 = 0.435 mole of K₃PO₄. Now K₃PO₄ is a strongly ionic salt which dissociate in solution as K₃PO₄=3K⁺ + [tex]PO_{4}^{3-}[/tex]. Thus 1 mole of K₃PO₄ produces 3 moles of K⁺ ions.
Thus, 0.435 mole K₃PO₄ produces (3×0.435) = 1.305 mole of K⁺ ion.
Thus 343 mL of 1.27 M K₃PO₄ solution contains 1.305 mole of K⁺ ions.
1 M or molar solution is defined as the solution in which 1 mole of a compound or substance is dissolved in 1 litre of total volume. The 1M is equal to 1 mole of the compound present in 1 L. The number of moles of potassium ions will be 1.305.
Given that,
- Molar solution of [tex]\text {K}_{3} \text {PO}_{4}[/tex] = 1.27 M
- Volume of solution = 343 mL
Now, calculating the number of moles in 343 mL,
- [tex]\dfrac{1.27}{1000}\times 343 &= 0.435 \; \text {moles of K}_{3}\text{PO}_{4}[/tex]
Tripotassium phosphate is an ionic salt, which will dissociate into 3[tex]\text{K}^{+} \text {and PO}_{4}^{3-}[/tex] in aqueous solution. It can be interpreted as 1 mole of tripotassium phosphate produces 3 moles of potassium ions.
Therefore, the 0.435 mole [tex]\text {moles of K}_{3}\text{PO}_{4}[/tex] of will produce = 3 X 0.435 = 1.305 mole of K+ ions. The 343 mL of 1.27M [tex]\text { K}_{3}\text{PO}_{4}[/tex] solution consists of 1.305 moles of potassium ions.
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