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b. NO(g) + Cl_2( g) → NOCl(g) + Cl( g) has the smaller orientation factor.

If the Cl_2 attacks NO from the left: Cl-Cl + N-O → Cl + Cl-N-O. Wrong products!

If the Cl_2 attacks NO from the right: N-O + Cl-Cl → N-O-Cl + Cl. Correct products!

a. O(g) + N2(g) → NO(g) + N(g)

If an O atom attacks from the left: O + N-N → O-N + N. Correct products!

If an O atom attacks from the right: N-N + O → N + N-O. Correct products!

Reaction b. has the smaller orientation factor because the molecules have a smaller chance of colliding from the correct direction.

No and Cl2 are in the correct orientation hence there is a smaller smaller orientation factor.

What is orientation?

We know that chemical reactions occur when molecules in the correct orientation collide with each other. This is  the natural outcome of the collsion theory. Hence, the orientation of molecules is very neccesary for collision to occur.

As a result of this, we know that,No and Cl2 are in the correct orientation hence there is a smaller orientation factor.

Learn more about orientation factor: https://brainly.com/question/14019685?