Respuesta :

for the imaginary plane the y-axis is the imaginary axis, therefore, 6 + 3i and -12 - 5i, is really just (6, 3) and (-12, -5).


[tex]\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{6}~,~\stackrel{y_1}{3})\qquad (\stackrel{x_2}{-12}~,~\stackrel{y_2}{-5}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-12+6}{2}~~,~~\cfrac{-5+3}{2} \right)\implies \left( \cfrac{-6}{2}~~,~~\cfrac{-2}{2} \right)\implies (-3,-1)\implies \boxed{-3 - i}[/tex]

abidemiokin

The midpoint of the segment with endpoints of 6 + 3i and −12 − 5i in complex form is -3 - i

Given the complex numbers  6 + 3i and −12 − 5i. We can write it in coordinate form (x. y)

x is the real part

y is the imaginary part

For the complex number 6 + 3i. the coordinate point will be (6, 3)

For the complex number -12 - 5i. the coordinate point will be (-12, -5)

Get the midpoint of both coordinates

[tex]M(x,y)=(\frac{6-12}{2}, \frac{3-5}{2})\\M(x,y)=(\frac{-6}{2},\frac{-2}{2} ) \\M(x,y) = (-3, -1)[/tex]

Hence the midpoint of the segment in complex form is -3 - i

Learn more here: https://brainly.com/question/3510899

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