Let us suppose, we pour x glass of water.
The given jug is of 6 liters. And the glass of water was seven- eighths of a liter. Hence, we have the below equation
[tex]\frac{7}{8} x= 6[/tex]
Now, in order to solve for x, we will divide 6 with 7/8. So, we have to divide.
[tex]x=\frac{6}{7/8} \\ \\ x=\frac{48}{7} \\ \\ x=6.9[/tex]
Hence, we can pour 7 glass of water. But the 7th glass is not full of water. It is partially full.
