denizkins
contestada

How do i solve g=(x-c)/x for x? I'm lost on problems like these with division problems and more than one x that I'm solving for.

Respuesta :

you can group all the x together and then factor out x and then divide.

g = (x-c)/x

multiply both sides by x and u get

gx = x - c

move all x terms together... subtract x from both sides

gx - x = -c

factor out x via reverse distributive property

x(g-1) = -c

divide both sides by g-1

x = -c/(g-1)

if you want to make it look like the other answer (they are both equivalent), if you factor out a negative 1 from the denominator, you get

[tex]x=\dfrac{-c}{-1(-g+1)} = \dfrac{-c}{-1(1-g)} = \dfrac{c}{1-g}[/tex]

Paounn

The idea is to bring x to the numerators:

You start by saying [tex]x\neq 0[/tex] (it's a denominator). Then you multiply both sides by x (which is legit, since you are multiplying for something which isn't zero). Then you get [tex]gx = x-c[/tex]. Add [tex] c-gx [/tex] to both sides, and you get - reading right to left - [tex] (1-g)x = c [/tex] and, AFTER stating that [tex] g \neq 1 [/tex] (you can't divide by zero!!) [tex] x= \frac {c}{1-g} [/tex]

Otras preguntas