An air-filled rubber ball has a diameter of 6 in. If the air pressure within the ball is increased until the diameter becomes 7 in., determine the average normal strain in the rubber.

Respuesta :

we are given

An air-filled rubber ball

[tex]d_0=6in[/tex]

[tex]d=7in[/tex]

we can use formula of the average normal strain in the rubber

[tex]\delta =\frac{\pi d - \pi d_0}{\pi d_0}[/tex]

now, we can plug values

and we get

[tex]\delta =\frac{\pi*7 - \pi*6}{\pi* 6}[/tex]

[tex]\delta =0.16667in/in[/tex]...........Answer