Answer: The new pressure of the gas is (A) 854.46 kPa.
The pressure of a given mass of gas at the absolute temperature 110 degrees K is 400 kPa.
The temperature is raised to 235 degrees K with constant volume.
Therefore,
Initial pressure [tex]P_{1}=400kPa[/tex]
Initial temperature [tex]T_{1}=110K[/tex]
Final temperature [tex]T_{2}=235K[/tex]
Final pressure[tex]P_{2}=?[/tex]
According to pressure law of gas,
[tex]\frac{P_{1} }{T_{1} }=\frac{P_{2} }{T_{2} }[/tex] ( at constant volume)[tex]P_{2}=\frac{P_{1}T_{2} }{T_{1} }[/tex]
[tex]P_{2}=\frac{400X235}{110}[/tex]
[tex]P_{2}=854.46kPa[/tex]
Thus, the required new pressure of the gas is 854.46 kPa.
