Answer: Theoretical mass of sodium sulphate ( [tex]Na_2SO_4[/tex] ) is 514.118 grams.
Explanation: For a given reaction,
[tex]2NaOH(aq.)+H_2SO_4(aq.)\rightarrow Na_2SO_4(s)+2H_2O(l)[/tex]
As NaOH is used in excess, therefore it is an excess reagent and [tex]H_2SO_4[/tex] is a limiting reagent as the quantity of the product will depend on it.
We are given 355 grams of [tex]H_2SO_4[/tex].
Molar mass of [tex]H_2SO_4[/tex] = 98.079 g/mol
Molar mass of [tex]Na_2SO_4[/tex] = 142.04 g/mol
1 mole of [tex]H_2SO_4[/tex] is producing 1 mole of [tex]Na_2SO_4[/tex], so
98.079 g/mol of [tex]H_2SO_4[/tex] will produce 142.04 g/mol of [tex]Na_2SO_4[/tex]
355 grams of [tex]H_2SO_4[/tex] will produce = [tex]142.04g/mol \times \frac{355g}{98.079g/mol}[/tex] of [tex]Na_2SO_4[/tex]
Mass of [tex]Na_2SO_4[/tex] = 514.118 grams
