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Hey there!

The pH of a weak base (in this case, pyridine is a weak base) is calculated by using the weak base equation, and then solving it.

C5H5N; Kb= 1.7 x 10⁻⁹

pH = -log [H⁺]

we can also say that pH = 14 + log [OH⁻]

Plugging into the weak base equation, we know that Kb = [OH⁻][BH⁺] / [B]

This can be solved using an ice chart, which will then simplify to :

Kb = [x][x] / [0.50-x]

We can assume that x is very small in comparison to the 0.5 , so we consider it zero.


Then plug in and solve for x.  1.79 *10-9 = x² / 0.5

x = 2.992 * 10⁻⁵

ince X is equal to the [OH⁻] concentration, we can plug it into the second pH equation, and get the pH!

pH = 14+ log 2.99 * 10⁻⁵

pH = 9.48

Hope that helps!

The pH of a 0.65 M solution of pyridine (C₅H₅N) is 9.52.  

The equation for the protonation of the base pyridine is the following:

C₅H₅N + H₂O ⇄ C₅H₅NH⁺ + OH⁻   (1)

The constant of the above reaction is:

[tex] K_{b} = \frac{[C_{5}H_{5}NH^{+}][OH^{-}]}{[C_{5}H_{5}N]} = 1.7 \cdot 10^{-9} [/tex]    (2)

To calculate the pH of the solution we need to use the following equation:

[tex] pH + pOH = 14 [/tex]      

[tex] pH = 14 - pOH = 14 - (-log[OH^{-}]) = 14 + log[OH^{-}] [/tex]   (3)

So, we need to find the concentration of the OH⁻ ions. Since pyridine is a weak base, at the equilibrium we have (eq 1):

C₅H₅N  +  H₂O  ⇄  C₅H₅NH⁺  +  OH⁻

0.65 - x                          x              x

After entering the values of [C₅H₅N] = 0.65-x, [C₅H₅NH⁺] = x, and [OH⁻] = x, into equation (2) we can find the concentration of OH⁻:

[tex] 1.7 \cdot 10^{-9} = \frac{[C_{5}H_{5}NH^{+}][OH^{-}]}{[C_{5}H_{5}N]} = \frac{x*x}{0.65 - x} [/tex]  

[tex] 1.7 \cdot 10^{-9}(0.65 - x) - x^{2} = 0 [/tex]  

Solving the above quadratic equation for x, we have:

[tex] x_{1} = -3.32 \cdot 10^{-5} M [/tex]

[tex] x_{2} = 3.32 \cdot 10^{-5} M [/tex]        

We can calculate the pH, after taking the positive value, x₂, (concentrations cannot be negative) and entering into equation (3):

[tex] pH = 14 + log[OH^{-}] = 14 + log(3.32 \cdot 10^{-5}) = 9.52 [/tex]  

Therefore, the pH of the solution of pyridine is 9.52.

Find more about pH here:

  • https://brainly.com/question/8834103?referrer=searchResults
  • https://brainly.com/question/11532683?referrer=searchResults      

I hope it helps you!    

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