Answer:
9. 3.6
10. 1.4
11. 5
Explanation:
It can help to draw a diagram relevant to the question. (See the attached for 3 diagrams.)
The radius of a circle is the same from the center to every point on the circle. This tells you HB = BC = 2; CD = DE = 1; EF = JF = 3.
The Pythagorean theorem tells you for sides X and Y and hypotenuse Z of a right triangle, the following relation is true:
... Z² = X² + Y²
Taking the square root, you have ...
... Z = √(X² +Y²)
_____
9. HD² = HB² +BD² . . . . where BD = BC+CD = 2+1 = 3
so we have
... HD = √(2² +3²) = √(4+9) = √13 ≈ 3.6
10. IE² = ID² +DE²
... IE = √(1² +1²) = √2 ≈ 1.4
11. JD² = JF² +FD² . . . . where FD = DE +EF = 1+3 = 4
... JD = √(3² +4²) = √(9+16) = √25 = 5
