How do you solve this geometry problem

From the Figure We can Notice that :
Opposite Side - AB = 1
Adjacent Side - OB = [tex]\sqrt{3}[/tex]
We know that :
[tex]Tan\theta = \frac{Opposite\:Side}{Adjacent\:Side}[/tex]
[tex]\implies Tan\theta = \frac{1}{\sqrt{3}}[/tex]
⇒ θ = 30°
We know that :
[tex]Sin\theta = \frac{Opposite Side}{Hypotenuse}[/tex]
⇒ [tex]Sin30 = \frac{1}{AO}[/tex]
⇒ [tex]\frac{1}{2} = \frac{1}{AO}[/tex]
⇒ AO = 2