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A 35-N bucket of water is lifted vertically 3.0 m and then returned to its original position. How much work did gravity do on the bucket during this process?

Respuesta :

While Going Down:

Work done = Potential Gravitational Energy = mass x acceleration due to gravity  x Height

= mgh

While Going Up:

Work done = Potential Gravitational Energy = mass x -acceleration due to gravity  x Height

= mgh

Wnet = mgh + (mgh)

= 0

asuwafohjames

The work done by gravity during the process is 0 J.

To calculate the work done by gravity in lifting the bucket, we use the formula below.

Assuming a positive work was done in bringing the bucket down and a negative work was done in lifting the bucket up.

Formula:

  • Work done by gravity = positive Work done to lift the bucket up+ Negative work done to lift the bucket down.
  • W = Fd+(-Fd)............... Equation 1

Where:

  • W = Work done by gravity
  • F = Weight of the bucket
  • d = vertical distance

From the question,

Given:

  • F = 35 N
  • d = 3 m

Substitute these values into equation 1

  • W = (35×3)+(-35×3)
  • W = 105-105
  • W = 0 J

Hence, the work done by gravity during the process is 0 J.

Learn more about work done here: https://brainly.com/question/8119756

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