raj and his sister zia are both at secondary school. Raj is three years older than zia. the sum of the squares of their ages is 369. How old are they?

Respuesta :

Let us assume age of zia = x years.

Raj is three years older than Zia.

Therefore, Raj age = (x+3).

Sum of squares of their ages = 369.

Therefore, we can set an equation as :

[tex]x^2 +(x+3)^2 = 369[/tex]

Let us expand [tex](x+3)^2[/tex] now.

[tex](x+3)^2 = x^2+ 6x+9[/tex]

[tex]x^2+x^2+ 6x+9 = 369.[/tex]

Subtracting 369 from both sides

[tex]2x^2+ 6x+9 -369 = 369 -369.[/tex]

[tex]2x^2+ 6x -360 =0[/tex]

Factoring quadratic

[tex]2\left(x-12\right)\left(x+15\right)=0[/tex]

[tex]x=12,\:x=-15[/tex]

We can't take negative value for age.

Therefore, Zia's age is 12 years and Raj age is 12+3 = 15 years.