Answer: The gravity's constant value is [tex]9.8 m/sec^2[/tex].
Explanation:
The given function shows the distance from the ground (in meters) at time t (in sec).
[tex]d(t)=-4.9t^2+50[/tex]
First derivative of displacement is velocity and the second derivative of displacement is acceleration.
Differentiate the given equation with respect to t.
[tex]v(t)=d'(t)=-9.8t+0[/tex]
Differentiate the above equation with respect to t.
[tex]a(t)=v'(t)=d''(t)=-9.8[/tex]
It is given that gravity is the only acceleration affecting the object and the negative sign shows the downward direction of the object.
Therefore, the gravity's constant value is [tex]9.8 m/sec^2[/tex].
