camhugh02
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A car travels at uniform acceleration over a distance of 440.0 m. Its initial velocity is 11.0 m/s. What is its final velocity after 20.0 s?

207.0 m/s
11.0 m/s
22.0 m/s
33.0 m/s

Respuesta :

x=v0t+1/2at^2

x=440 m

v0=11 m/s

t=20 s

Solve for a

440=11(20)+1/2a20^2

440=220+1/2a*400

220=1/2a*400

440=400a

1.1=a

Now we can use V=V0+at

V=11+1.1*20

V=33 m/s


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